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Binary to Excess-3 Converter

Convert binary numbers into Excess-3 (XS-3 / Stibitz) self-complementing code. Designed for software developers, electrical engineers, students, and computer architecture researchers requiring deterministic client-side accuracy.

Engine: Client-Side Verified (0ms Latency)

Enter binary sequence (e.g. 1001 for 9).

Calculated Output

Primary Representation
Calculating...

Step-by-Step Mathematical Proof

Active Derivation
Ready. Enter input above to generate derivation.
Concept

What Is Binary to Excess-3 Converter?

Excess-3 code (XS-3 or Stibitz code) is an unweighted, self-complementing digital encoding formed by adding 3 (binary 0011) to each digit of an 8421 BCD number.

Methodology

How Does It Work?

Convert the binary number to its decimal digits. Add 3 to each decimal digit (d + 3), then convert each resulting sum into a 4-bit binary nibble.

Formula & Rules

Mathematical Algorithm

\text{XS-3}_k = (d_k + 3)_{10} \xrightarrow{} 4\text{-bit binary}
Worked Problem

Step-by-Step Example

Convert binary 1001_2 (decimal 9) to Excess-3: Digit = 9 9 + 3 = 12 12 in 4-bit binary is 1100_2 Excess-3: 1100.

Important Rules & Edge Cases

  • Every decimal digit maps to a 4-bit nibble from 0011 (0+3) to 1100 (9+3).
  • It is self-complementing: bitwise inverting an XS-3 code produces the 9’s complement of the decimal digit.

Practical Applications in Engineering

  • Arithmetic simplification in early electromechanical and decimal computers.
  • Fast decimal 9’s complement generation without borrow circuitry.
  • Educational instruction in digital logic coding.

Common Mistakes to Avoid

  • Caution: Adding 3 to the total binary number instead of adding 3 to each individual decimal digit.
  • Caution: Allowing nibble sums greater than 1100 (12).
FAQ

Frequently Asked Questions

Why is Excess-3 called a self-complementing code?

Because taking the 1’s complement (inverting all bits) of an Excess-3 nibble automatically yields the Excess-3 code of that digit’s 9’s complement (e.g. inverting 0 gives 9).